select c.categories_id, cd.categories_name from categories c, categories_description cd where parent_id = '0' and c.categories_id = cd.categories_id and cd.language_id = '1' order by sort_order, cd.categories_name
[TEP STOP]
2006 - MySQL server has gone away
select count(*) as total from sessions where sesskey = 'eea791b7e2a868b2ce7768775d802e1f'
